P(x)=x^2+10

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Solution for P(x)=x^2+10 equation: 



(P)=P^2+10

We move all terms to the left:

(P)-(P^2+10)=0

We get rid of parentheses

-P^2+P-10=0

We add all the numbers together, and all the variables

-1P^2+P-10=0

a = -1; b = 1; c = -10;
Δ = b2-4ac
Δ = 12-4·(-1)·(-10)
Δ = -39
Delta is less than zero, so there is no solution for the equation

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